Chapter 6: Answer 3

a) McVc = MdVd

(18 M)(Vc) = (0.50 M)(500 mL)

Vc = (0.50 M)(500 mL)/18 M = 14 mL

b) DH = (sp. ht.)(mass)(DT)

DH = (4.2 J/g*°C)(100g+14g)(26.8-20.1°C)

DH = (4.2 J/g*°C)(114g)(6.7°C) = 3208 J = 3.2 KJ

Note: assume that the density of the sulfuric acid solution is also 1.00 g/mL